+26367 Find angle PRQ,
\(\text{Let $\angle PRQ = x $}\)
\(\begin{array}{|rcll|} \hline y+2*90^\circ + \theta &=& 360^\circ \\ y + \theta &=& 180^\circ \\ \mathbf{y} &=& \mathbf{180^\circ-\theta} \\\\ 120^\circ+130^\circ+y+x &=& 360^\circ \\ 250^\circ+y+x &=& 360^\circ \\ y+x &=& 110^\circ \quad | \quad \mathbf{y=180^\circ-\theta} \\ 180^\circ-\theta+x &=& 110^\circ \\ -\theta+x &=& -70^\circ \\ \mathbf{\theta} &=& \mathbf{70^\circ +x} \\\\ x &=& \dfrac{\theta}{2} \quad | \quad \mathbf{\theta=70^\circ +x} \\\\ x &=& \dfrac{70^\circ +x}{2} \\\\ 2x &=& 70^\circ + x \\ \mathbf{ x} &=& \mathbf{70^\circ} \\ \hline \end{array}\)
