Solve for n:
(7 n)/10-2 = (2 n)/5+1
Put each term in (7 n)/10-2 over the common denominator 10: (7 n)/10-2 = (7 n)/10-(20)/10:
(7 n)/10-(20)/10 = (2 n)/5+1
(7 n)/10-(20)/10 = (7 n-20)/10:
(7 n-20)/10 = (2 n)/5+1
Put each term in (2 n)/5+1 over the common denominator 5: (2 n)/5+1 = (2 n)/5+5/5:
(7 n-20)/10 = (2 n)/5+5/5
(2 n)/5+5/5 = (2 n+5)/5:
(7 n-20)/10 = (2 n+5)/5
Multiply both sides by 10:
(10 (7 n-20))/10 = (10 (2 n+5))/5
(10 (7 n-20))/10 = 10/10×(7 n-20) = 7 n-20:
7 n-20 = (10 (2 n+5))/5
10/5 = (5×2)/5 = 2:
Answer: |
| 7 n-20 = 2 (2 n+5), n=10
