The distance between the points A and B is √5. If A=(a,−1) and B=(2,2a−7), then find the sum of all possible values of a.
Square of the distance formula
(a - 2)^2 + (2a - 7 + 1)^2 = 5
(a -2)^2 + ( 2a - 6)^2 = 5
a^2 - 4a + 4 + 4a^2 - 24a + 36 = 5
5a^2 - 28a + 35 = 0
Sum of possible a's = -(-28) / 5 = 28 / 5
+900 
