Joan tries to solve a really hard problem once each day. She has a 1/4 probability of solving it each day. What is the probability that she will solve it before her sixth try?
BEFORE her 6th try is 5 tries
The probability that she DOESN"T solve it daily is 3/4
1- (3/4)5 = 781/1024 = 76.3% ???
BEFORE her 6th try is 5 tries
The probability that she DOESN"T solve it daily is 3/4
1- (3/4)5 = 781/1024 = 76.3% ???
Joan tries to solve a really hard problem once each day. She has a 1/4 probability of solving it each day. What is the probability that she will solve it before her sixth try?
EPs way is the best way.
Here is another method though ![]()
Prob that she solves it on her first try =1/4
Prob that she solves it on her second try = 3/4*1/4 = 3/16
Prob that she solves it on her third try = (3/4)^2 * 1/4 = 9/64
Prob that she solves it on her forth try = (3/4)^3 * 1/4 = 27/256
Prob that she solves it on her f5th try = (3/4)^4 * 1/4 = 81/1024
1/4(1+3/4+9/16+27/64+81/256) = 0.7626953125 equals a approx 76.3%