Solve for x:
2 x^2+3 x-7 = x^2+5 x+39
Subtract x^2+5 x+39 from both sides:
x^2-2 x-46 = 0
Add 46 to both sides:
x^2-2 x = 46
Add 1 to both sides:
x^2-2 x+1 = 47
Write the left hand side as a square:
(x-1)^2 = 47
Take the square root of both sides:
x-1 = sqrt(47) or x-1 = -sqrt(47)
Add 1 to both sides:
x = 1+sqrt(47) or x-1 = -sqrt(47)
Add 1 to both sides:
Answer: | x = 1+sqrt(47) or x = 1-sqrt(47)
