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Can someone please help me. with 5 and 6?

 Apr 10, 2020
 #1
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(x^2)^5                 x^10

_________  =    _________   =   2^15 * x^10  =  32768x^10 

 (2^(-3))^5             2^(-15)

 

 

Note  that  in the second  one  the x^(-2)  terms  "cancel"   so we are left with

 

y^5 / y^7   =    y ^(5 - 7)  =  y^(-2)  =     1  / y^2

 

 

cool cool cool

 Apr 10, 2020

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