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When (a+b)^5 is expanded using the Binominal Theroem for certain values of a and b, the second term is 15, and the third term is 60. Find the first term

 Sep 26, 2021
 #1
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1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

 

(a+b)^5 = a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

5a^4b = 15

10a^3b^2 = 60

 

Can you take it from here?

 

=^._.^=

 Sep 26, 2021

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