When (a+b)^5 is expanded using the Binominal Theroem for certain values of a and b, the second term is 15, and the third term is 60. Find the first term
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
(a+b)^5 = a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5
5a^4b = 15
10a^3b^2 = 60
Can you take it from here?
=^._.^=
