+4 The perimeter of the rectangle is 596 yards. The length of it is 2 yards less than quadruple the width. What are the dimensions of the rectangle?
This is all the info given
+9466 Let's call the length of the rectangle, in yards, L .
Let's call the width of the rectangle, in yards, W .
The perimeter of the rectangle is 596 yards, so....
L + L + W + W = 596
Let's solve this equation for L . Comine like terms.
2L + 2W = 596
Subtract 2W from both sides of the equation.
2L = 596 - 2W
Divide through by 2 .
L = 298 - W
Its length is 2 yards less than 4 times its width, so...
L = 4W - 2
Since L = 298 - W we can replace L with 298 - W .
298 - W = 4W - 2
Add 2 to both sides, and add W to both sides.
298 + 2 = 4W + W
Combine like terms.
300 = 5W
Divide both sides by 5 .
60 = W
Now we can use this value for the width to find the length.
L = 298 - W
L = 298 - 60
L = 238
So the width is 60 yards and the length is 238 yards.
+9466 Let's call the length of the rectangle, in yards, L .
Let's call the width of the rectangle, in yards, W .
The perimeter of the rectangle is 596 yards, so....
L + L + W + W = 596
Let's solve this equation for L . Comine like terms.
2L + 2W = 596
Subtract 2W from both sides of the equation.
2L = 596 - 2W
Divide through by 2 .
L = 298 - W
Its length is 2 yards less than 4 times its width, so...
L = 4W - 2
Since L = 298 - W we can replace L with 298 - W .
298 - W = 4W - 2
Add 2 to both sides, and add W to both sides.
298 + 2 = 4W + W
Combine like terms.
300 = 5W
Divide both sides by 5 .
60 = W
Now we can use this value for the width to find the length.
L = 298 - W
L = 298 - 60
L = 238
So the width is 60 yards and the length is 238 yards.
