The perimeter of the rectangle is 596 yards. The length of it is 2 yards less than quadruple the width. What are the dimensions of the rectangle?

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herrstein1010 Apr 11, 2018

#1**+1 **

Let's call the length of the rectangle, in yards, L .

Let's call the width of the rectangle, in yards, W .

The perimeter of the rectangle is 596 yards, so....

L + L + W + W = 596

Let's solve this equation for L . Comine like terms.

2L + 2W = 596

Subtract 2W from both sides of the equation.

2L = 596 - 2W

Divide through by 2 .

L = 298 - W

Its length is 2 yards less than 4 times its width, so...

L = 4W - 2

Since L = 298 - W we can replace L with 298 - W .

298 - W = 4W - 2

Add 2 to both sides, and add W to both sides.

298 + 2 = 4W + W

Combine like terms.

300 = 5W

Divide both sides by 5 .

60 = W

Now we can use this value for the width to find the length.

L = 298 - W

L = 298 - 60

L = 238

So the width is 60 yards and the length is 238 yards.

hectictar Apr 11, 2018

#1**+1 **

Best Answer

Let's call the length of the rectangle, in yards, L .

Let's call the width of the rectangle, in yards, W .

The perimeter of the rectangle is 596 yards, so....

L + L + W + W = 596

Let's solve this equation for L . Comine like terms.

2L + 2W = 596

Subtract 2W from both sides of the equation.

2L = 596 - 2W

Divide through by 2 .

L = 298 - W

Its length is 2 yards less than 4 times its width, so...

L = 4W - 2

Since L = 298 - W we can replace L with 298 - W .

298 - W = 4W - 2

Add 2 to both sides, and add W to both sides.

298 + 2 = 4W + W

Combine like terms.

300 = 5W

Divide both sides by 5 .

60 = W

Now we can use this value for the width to find the length.

L = 298 - W

L = 298 - 60

L = 238

So the width is 60 yards and the length is 238 yards.

hectictar Apr 11, 2018