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# need help!

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The perimeter of the rectangle is 596 yards. The length of it is 2 yards less than quadruple the width. What are the dimensions of the rectangle?

This is all the info    given

Apr 11, 2018
edited by herrstein1010  Apr 11, 2018

#1
+7612
+1

Let's call the length of the rectangle, in yards,  L  .

Let's call the width of the rectangle, in yards,  W .

The perimeter of the rectangle is 596 yards, so....

L + L + W + W   =   596

Let's solve this equation for  L . Comine like terms.

2L + 2W   =   596

Subtract  2W  from both sides of the equation.

2L   =   596 - 2W

Divide through by  2 .

L   =   298 - W

Its length is 2 yards less than 4 times its width, so...

L   =   4W - 2

Since   L  =  298 - W   we can replace  L  with  298 - W .

298 - W   =   4W - 2

298 + 2   =   4W + W

Combine like terms.

300   =   5W

Divide both sides by  5 .

60   =   W

Now we can use this value for the width to find the length.

L   =   298 - W

L   =   298 - 60

L   =   238

So the width is 60 yards and the length is 238 yards.

Apr 11, 2018

#1
+7612
+1

Let's call the length of the rectangle, in yards,  L  .

Let's call the width of the rectangle, in yards,  W .

The perimeter of the rectangle is 596 yards, so....

L + L + W + W   =   596

Let's solve this equation for  L . Comine like terms.

2L + 2W   =   596

Subtract  2W  from both sides of the equation.

2L   =   596 - 2W

Divide through by  2 .

L   =   298 - W

Its length is 2 yards less than 4 times its width, so...

L   =   4W - 2

Since   L  =  298 - W   we can replace  L  with  298 - W .

298 - W   =   4W - 2

298 + 2   =   4W + W

Combine like terms.

300   =   5W

Divide both sides by  5 .

60   =   W

Now we can use this value for the width to find the length.

L   =   298 - W

L   =   298 - 60

L   =   238

So the width is 60 yards and the length is 238 yards.

hectictar Apr 11, 2018