Find the smallest positve n such that:
N≡6(mod12),N≡6(mod18),N≡6(mod24),N≡6(mod30),N≡6(mod60).
Melody:
The smallest N is 6. The LCM of[12, 18, 24, 30, 60] = 360. Therefore:
N = 360k + 6, where k = 0, 1, 2, 3.........etc.
Hey Guest!
LCM [12, 18, 24, 30, 60] = 360
N = 360k + 6.
6 is your answer.
Guest is right, my previous answer was wrong.
I hope this helped,
gavin
The smallest N is 6, the rest of my answer was incorrect.
Yes you are right ....
I appologise for my incorrect answer :)