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# Need help

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What are the solutions to the trigonometric equation on the interval [0,2π)?

2cos^2 x=cos x

Select all correct solutions.

0

π/6

π/3

π/2

2π/3

5π/6

π

7π/6

4π/3

3π/2

5π/3

11π/6

Apr 22, 2021

### 1+0 Answers

#1
+11422
+1

What are the solutions to the trigonometric equation on the interval [0,2π)?

2cos^2 x=cos x

Select all correct solutions.

Hello Guest!

$$2cos^2 x=cos x\\ 2cos^2 x-cos x=0\\ cos x=0\\ \color{blue}x\in \{\frac{\pi}2{},\frac{3\pi}{2}\}$$

$$2cosx-1=0\\ cosx=0.5\\ \color{blue}x\in \{\frac{\pi}{3},\frac{5\pi}{3}\}$$

Select all correct solutions.

0

π/6

π/3

π/2

2π/3

5π/6

π

7π/6

4π/3

3π/2

5π/3

11π/6

2π/3

5π/6

π

7π/6

4π/3

3π/2

5π/3

11π/6

!

Apr 22, 2021
edited by asinus  Apr 22, 2021
edited by asinus  Apr 22, 2021