What are the solutions to the trigonometric equation on the interval [0,2π)?
2cos^2 x=cos x
Select all correct solutions.
0
π/6
π/3
π/2
2π/3
5π/6
π
7π/6
4π/3
3π/2
5π/3
11π/6
What are the solutions to the trigonometric equation on the interval [0,2π)?
2cos^2 x=cos x
Select all correct solutions.
Hello Guest!
\(2cos^2 x=cos x\\ 2cos^2 x-cos x=0\\ cos x=0\\ \color{blue}x\in \{\frac{\pi}2{},\frac{3\pi}{2}\}\)
\(2cosx-1=0\\ cosx=0.5\\ \color{blue}x\in \{\frac{\pi}{3},\frac{5\pi}{3}\}\)
Select all correct solutions.
0
π/6
π/3
π/2
2π/3
5π/6
π
7π/6
4π/3
3π/2
5π/3
11π/6
2π/3
5π/6
π
7π/6
4π/3
3π/2
5π/3
11π/6
!