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Farmer Deanna looks out her window and counts a total of 64 legs on a total of 20 animals. If she has only sheep and chickens, how many of each does she have? (Hint: Sheep have 4 legs each and chickens 2 legs each.

 Mar 3, 2020

Best Answer 

 #1
avatar+887 
+2

Hey!

 

Let's start by setting two variables, 

 

\(S = \text{sheep}\)

\(C = \text{chicken}\)

 

Once we have our variables we can go ahead and make our equations:

 

1.) The easiest equation that we can make with these two variables is with the total # of animals.

 

The number of sheep + The number of chickens = The total # of animals,

So we get the equation: \(S + C = 20\).

 

2.) Now, we are given that sheep have \(4\) legs and chickens have \(2\) legs.

 

(The number of sheep x The number of legs each sheep has) + (The number of chickens x The number of legs each chicken has) = The total # of legs.

So we get the equation \(4S + 2C = 64\)

 

Now that we have our two equations,

\(4S + 2C = 64\)

\(S + C = 20\),

 

You can use the two equations to either substitute the variables or eliminate them to find your answer. cool

 Mar 3, 2020
 #1
avatar+887 
+2
Best Answer

Hey!

 

Let's start by setting two variables, 

 

\(S = \text{sheep}\)

\(C = \text{chicken}\)

 

Once we have our variables we can go ahead and make our equations:

 

1.) The easiest equation that we can make with these two variables is with the total # of animals.

 

The number of sheep + The number of chickens = The total # of animals,

So we get the equation: \(S + C = 20\).

 

2.) Now, we are given that sheep have \(4\) legs and chickens have \(2\) legs.

 

(The number of sheep x The number of legs each sheep has) + (The number of chickens x The number of legs each chicken has) = The total # of legs.

So we get the equation \(4S + 2C = 64\)

 

Now that we have our two equations,

\(4S + 2C = 64\)

\(S + C = 20\),

 

You can use the two equations to either substitute the variables or eliminate them to find your answer. cool

KnockOut Mar 3, 2020

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