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Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to $7$ times the largest of the seven integers. What is the smallest integer that Pearl wrote down?

 Apr 3, 2024
 #1
avatar+945 
+1

 

Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to $7$ times the largest of the seven integers. What is the smallest integer that Pearl wrote down?   

 

Call the smallest integer x.    

 

  (x) + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6)  =  7 • (x+6)       

 

                                                                   7x + 21  =  7x + 42   

 

I don't see how you can get a solution to the problem as stated.   

 

.

 Apr 3, 2024
 #2
avatar+129690 
+1

Bosco is correct......no solution.....

 

cool cool cool

CPhill  Apr 3, 2024

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