Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to $7$ times the largest of the seven integers. What is the smallest integer that Pearl wrote down?
Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to $7$ times the largest of the seven integers. What is the smallest integer that Pearl wrote down?
Call the smallest integer x.
(x) + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) = 7 • (x+6)
7x + 21 = 7x + 42
I don't see how you can get a solution to the problem as stated.
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