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2.) Consider the rational expression .

  [4x^2-4] /  [x^2 + 4x + 3]

Select true or false for each statement:

 

4 is a factor of the numerator: 

 

x+1 is a factor of the denominator

 

the denominator has 2 terms

 

the numerator has 2 terms

 Oct 19, 2018
edited by whosmans  Oct 19, 2018
 #1
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\(\dfrac{4x^2-4}{x^2+4x+3} = \dfrac{4(x^2-1)}{(x+3)(x+1)}=\dfrac{4(x+1)(x-1)}{(x+3)(x+1)}\)

 

True

 

True

 

This is a bit tricky.  Clearly there are two terms in both the numerator and denominator as written but we should cancel out the (x+1) term in both the numerator and denominator and obtain

 

\(\dfrac{4(x-1)}{x+3}\)

 

This has only a single term in both the numerator and denominator.

 

The answer your teacher wants to see depends on them.

 Oct 19, 2018

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