The polynomial has degree 3. If f(-1) = 15, f(0) = 0 , f(-1) = 5, and f(2) = 12, then what are the -intercepts of the graph of f?
Please explain the answer, because I would like to know how you arrive at the solution
f(-1) = 15, f(0) = 0 , f(-1) = 5, and f(2) = 12 ????
nvm i got the answer, but it's f(1)= -5
The polynomial has degree 3. If f(-1) = 15, f(0) = 0 , f(1) = -5, and f(2) = 12, then what are the -intercepts of the graph of f?
+11 
