Can someone help with this problem? I'm totally stuck.
The police department is keeping track of distracted drivers and accidents. They have found that if a driver is distracted, the driver has a 30% chance of being in an accident. If the driver is not distracted, the driver has a 2% chance of being in an accident. The probability of a driver being distracted is 10%. If needed, create a tree diagram on a separate piece of paper. Then use the diagram to answer the questions.
a. What is the probability a driver will be in an accident? Explain.
b. What is the probability that a driver who was in an accident was distracted? Explain
+128408
.02 (accident)
.90 (not distracted)
.98(no accident)
.30(accident)
.10 (distracted)
.70 (no accident)
a. P(accident) = P ( not distracted and accident) + P ( distracted and accident) =
(.90) (.02) + (.10) (.30) =
0.048 =
4.8%
b. P ( distracted and accident) = (.30)(.10) = 0.03 = 3%
