Let f(x) be a linear function. Given that f(6) - f(2) = 12, find f(12) - f(2).
If it is a linear function, it must have a constant slope: m = [ y2 - y1 ] / [ x2 - x1 ]
For this problem: if x2 = 6 and x1 = 2, then y2 = f(6) and y1 = f(2)
---> m = [ y2 - y1 ] / [ x2 - x1 ] ---> m = 12 / [ 6 - 2 ]
---> m = 12 / 4
---> m = 3
---> m = [ y2 - y1 ] / [ x2 - x1 ] ---> 3 = [ f(12) - f(2) ] / [ 12 - 2 ]
---> 3 = [ f(12) - f(2) ] / [ 10
---> 30 = f(12) - f(2)