need help

 

Use tangent to find angle AQB 

 

90^o – AQB = AQR 

 

CQR = AQR 

 

90^o – CQR = CQD  

 

Use tangent to find length of QD  

 

BD = 15 + QD  

_.

Similar triangles:

 

QD = 19.2/32  * 15 

then

QD + 15 = BD