1. Explain why the equation x+1/x-3 = 4/x-3 has no solution.
2 What are the domain restrictions for the following expression: 2x-8 / x^2-6x+8 and why are these values restrictions?
\(x+1 = 4 \Rightarrow x=3\\ \text{however 3 is not in the domain of either side of the equation (no division by 0)}\)
\(\text{again the point is no dividing by 0}\\ x^2-6x+8 = (x-4)(x-2) = 0 \text{ when }x=4, \text{ or }x=2\\ \text{Thus neither 4 nor 2 are included in the domain}\)
.\(x+1 = 4 \Rightarrow x=3\\ \text{however 3 is not in the domain of either side of the equation (no division by 0)}\)
\(\text{again the point is no dividing by 0}\\ x^2-6x+8 = (x-4)(x-2) = 0 \text{ when }x=4, \text{ or }x=2\\ \text{Thus neither 4 nor 2 are included in the domain}\)