+490 Bob Shoudt was a competitive eating champion for salmon chowder, in which he consumed a whopping 23.4 pounds of chowder in 6.00 minutes. Given that 1 kg = 2.20 pounds, at what rate did Bob eat this chowder in grams per second?
+397 \(23.4*2.20 = 51.48\). This means that there was \(51.48\) kg of chowders eaten in \(6\) minutes. \(51.48\) kg = \(51480\) g. There are \(3600\) seconds in \(6\) minutes. Our fraction is \(\frac{51480}{3600} = \frac{1287}{90} = \frac{143}{10}\) chowder eaten in grams per second.
- Daisy
