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Bob Shoudt was a competitive eating champion for salmon chowder, in which he consumed a whopping 23.4 pounds of chowder in 6.00 minutes. Given that 1 kg = 2.20 pounds, at what rate did Bob eat this chowder in grams per second?

whosmans  Aug 29, 2018
 #1
avatar+348 
+2

\(23.4*2.20 = 51.48\). This means that there was \(51.48\) kg of chowders eaten in \(6\) minutes. \(51.48\) kg = \(51480\) g. There are \(3600\) seconds in \(6\) minutes. Our fraction is \(\frac{​​​​51480}{3600} = \frac{1287}{90} = \frac{143}{10}\) chowder eaten in grams per second.

 

- Daisy

dierdurst  Aug 29, 2018
 #2
avatar+3277 
+1

But, shouldn't you divide 23.4 by 2.20?

tertre  Aug 29, 2018
 #3
avatar+348 
+1

Haha, that's right! Sorry, I made that mistake. Thanks for correcting me, Terte!

 

- Daisy

dierdurst  Aug 29, 2018
 #4
avatar+3277 
0

No problem!

tertre  Aug 29, 2018
 #5
avatar+15 
0

so wait did u correct now or wat cuz im very confused

finnmathwiz  Sep 6, 2018

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