Hi! I need some assistance with these two problems. Thanks in advance!

1)

2)

Guest Sep 21, 2019

#1**+2 **

2. Hint: Add 3 to both sides, then square both sides.

Subsituting 0 will get a complex number

1.) Here is an example

x=2 is has potential for extraneous roots because if you square both sides, and get x^{2}=4, there are other possible solutions that DON'T solve the original equation.

Based on that, what do you think the answer is?

CalculatorUser Sep 21, 2019

#6**+2 **

Solve for x:

sqrt(x^2 - 9) - 3 = 0

Isolate terms with x to the left hand side.

Add 3 to both sides:

sqrt(x^2 - 9) = 3

Eliminate the square root on the left hand side.

Raise both sides to the power of two:

x^2 - 9 = 9

Isolate terms with x to the left hand side.

Add 9 to both sides:

x^2 = 18

Eliminate the exponent on the left hand side.

Take the square root of both sides:

**x = 3 sqrt(2) or x = -3 sqrt(2)**

Guest Sep 21, 2019