What is the area of triangle BCD to the nearest tenth of a square inch? Use special right triangles to help find the height. Show work
We have a 30-60-90 right triangle
The side opposite the 30° angle forms the base of the triangle
The side opposite the 60° angle forms the height and is √3 times the base
So....the area is
(1/2)(base)(height) =
(1/2)(8) (8√3) =
32√3 ≈
55.4 in^2
