The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 108 feet in height?

Guest Nov 25, 2019

#1**0 **

2 second= 51+51=102 feets

in 1/100 second, 0.51 feet is climbed

well 108-102 feets = 6 feets

We know that 1/100 second = 0.51 feet

so in order to find these 6 feets

0.51 *x= 6

Specific number of seconds is multiplied to find the feets

x=6/0.51=11.764 approx.=11.8

2:11.8 (Second, second/100)

approx

2 seconds and 11.8 sec/100

2.12 seconds!

Guest Nov 25, 2019