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 Feb 5, 2015

Best Answer 

 #1
avatar+129852 
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Note, √( 1 - 1/x^2)  =

√(x^2 - 1) * 1 / √(x^2)

But, by the absolute value property  1 / √(x^2) = 1 / l x l  because  x could  be negative

Therefore,

(1/ √(x^2)) * x^2  =  (1 / l x l ) * x^2  .... and x^2  = √(x^2) * √(x^2) = l x l * l x l

So, we end up with

l x l * l x l / l x l   =  l x l

And, of course, this is multiplied by √(x^2 - 1)

 

 Feb 5, 2015
 #1
avatar+129852 
+5
Best Answer

Note, √( 1 - 1/x^2)  =

√(x^2 - 1) * 1 / √(x^2)

But, by the absolute value property  1 / √(x^2) = 1 / l x l  because  x could  be negative

Therefore,

(1/ √(x^2)) * x^2  =  (1 / l x l ) * x^2  .... and x^2  = √(x^2) * √(x^2) = l x l * l x l

So, we end up with

l x l * l x l / l x l   =  l x l

And, of course, this is multiplied by √(x^2 - 1)

 

CPhill Feb 5, 2015

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