need to find the one equivalent to n+3n+2n(squared) using distributive property

need to find the one equivalent to n+3n+2n(squared) using distributive property

2n(n+2)

2n(n+1)

n(n+2)

2n(2n+2)

$$n+3n+2n^2 \\
= n(1+3+2n) \\
= n ( 4+2n ) \\
= n * 2(2+n) \\
=2n(n+2)$$

the answers in the one before are the options. sorry!

nevermind it wasnt an answer