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1. Which expression is equal to 7ab^5/56a^3b^2 ?
A. 8b^3/a^2
B. 8a^3/b^2
C. b^3/8a^3
D. b^3/8a^2

2. Which expression is equal to (x−3)(x−2)/(x+3)(x−3) ?
A x−3/x+3
B. x−2/x−3
C. x−2/x+3
D. x+2/x+3

 

3.

Simplify.

9−x2/9x+27

 

A. 3−x/9

B. 3−x

C. x+3/9

D. x−3/9

 Jan 9, 2020
edited by Guest  Jan 9, 2020
 #1
avatar+20217 
+2

1  the 7 /56 part simplifies to   1/8

     the a /a^3   simplifies to   1/a^2

       the b^5/b^2  simplifies to  b^3

         and you are left with     b^3/8a^2

 

2  the two (x-3) terms vcancel each other and you are left with

   (x-2)/(x+3)

 

3 unclear what ya got there

    can you include the parentheses?

 Jan 9, 2020
 #2
avatar+18258 
+1

I think that the third problem is:  (9-x2) / (9x + 27)

This, when factored becomes:  [ (3-x)(3+x) ] / [ 9(x+3) ]

Since (3+x) cancels (x+3):           (3-x) / 9

 Jan 9, 2020

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