Find f^-1 for the function f(x)=\root(3)(x-2)+8
Find f^-1 for the function f(x)=sqrt(3)(x-2)+8
The inverse function is: (x+2 sqrt(3)-8)/sqrt(3)
\(\text{Find } f^{-1}\text{ for the function }f(x)=\sqrt{(3)(x-2)+8}\)
\(y = \sqrt{(3)(x-2)+8}\)
\(y^2=(3)(x-2)+8\\ y^2=3x+2\\ y^2-2=3x\\ x = \dfrac{y^2-2}{3}\\ y=\dfrac{x^2-2}{3}\)
The inverse function is \(f(x)=\dfrac{x^2-2}{3}\)
