A square piece of paper is folded once so that one pair of opposite corners coincide. When the paper is unfolded, two congruent triangles have been formed. Given that the area of the original square is 49 square inches, what is the number of inches in the perimeter of one of these triangles? Express your answer in simplest radical form.
EDIT: I think it's 24.5 but that's not in radical form...
I tried it with a 4x 4 piece of paper....LOL!!!
Two isosceles right triangles are formed....with equal sides of 7 inches and a hypotenuse of 7√2 inches
The perimeter is
7 ( 1 + 1 + √2)
7 ( 2 + √2 ) in ≈ 23.89 in