what would 3ln(x+4)-5=3 be?
2\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
FIRST add 5 to both sides to get:
3ln(x+4) = 8 then divide by 3
ln (x+4) = 8/3 then e
x+4 = e^(8/3)
x+ 4 = 14.3919
x = 10.3919
~jc
Nice job, Jc!! :)
Solve for x: 3 log(x+4)-5 = 3 Add 5 to both sides: 3 log(x+4) = 8 Divide both sides by 3: log(x+4) = 8/3 Cancel logarithms by taking exp of both sides: x+4 = e^(8/3) Subtract 4 from both sides: Answer: | x = e^(8/3)-4
