The frictional (tangential) force applied to the foot of a runner is 300 N, directed posteriorly. At the same time an upward normal force of 1490 N acts on the same foot. What is the angle formed between the horizontal and the vector that is the resultant (sum) of these two forces acting on the foot? Give your answer to the nearest 0.1 degrees
+37084 Tangent of angle relative to horizontal is given by
TAN = opposite / adjacent = 1490 /(- 300) = -78.616 degrees from 180 degrees or 101.4 degrees from the 'zero' angle portion of the horizontal....(when rounded to the nearest 0.1 degree)
