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Calculate the gravitational force on a 6.50*10^2 kg that is 4.15x10^6m above the surface of the Earth?

 Apr 14, 2016
 #1
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F = G m1 x m2 / d^2  G= grav constant = 6.673 x10^-11

m1= 5.98 x 10^24   (earth mass)

 

6.673 x 10^-11   x   5.98 x 10^24   x  6.5 x 10^2  /  (6.38 x 10^6 + 4.15 x 10^6)^2

259.37 x 10^15 / (10.53 X 10^6)^2

2.339 X 10^3  N

 

(edited....forgot to SQUARE the denominator)

 Apr 14, 2016
edited by ElectricPavlov  Apr 14, 2016
 #2
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Calculate the gravitational force on a 6.50*10^2 kg that is 4.15x10^6m above the surface of the Earth?

 

F=[G. M. m] / r^2

F=[6.67 x 10-11 . 5.987 x 10^24 . 6.5 x 10^2] / [6,371,000 + 4,150,000]^2

F=2,344.95 newtons-gravitational force on the body.

 Apr 14, 2016
 #3
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ElectricPavlov: You forgot to square d or r in my case!!! See below.

 Apr 14, 2016

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