+0

# nobody knows the title of this post

+1
294
7

ok people, i have a question,

can 418 be spilt into groups of three where an integer is less than 180?

all of the integers have to be different and they must be in the format a+b+c= 480.

if there are any integers, please list them and explain why these work.

if not, prove that there can be no such integers of this kind.

Thanks!

(idk if this is a duplicate question but oh well if it is)

Jun 22, 2019
edited by Guest  Jun 22, 2019

#6
+2

I wrote a short code and listed all 3-digit combinations and they came out to =7,260 !!. Here is the code:

a=1; b=1;d=1;p=0;c=a + b + d; if(c==418, goto6, goto8);p=p+1;printp," - ",c, a, b, d; a++;if(a<180, goto4, 0);a=1;b++;if(b<180, goto4, 0);a=1;b=2;d++;if(d<180, goto4,0)

P.S. I hope that he/she doesn't want them ALL listed!.

Jun 23, 2019

#1
0

i *think* this is a math question, well i think its math? but still

Jun 22, 2019
#2
+8205
+1

418 or 480?

And did you mean that whether 3 integers (a, b, and c) can be found such that $$a< b< c<180$$ and $$a + b + c = 418\text{(or 480)}$$?

Jun 22, 2019
#3
0

i meant 418, i accidentally wrote 480. and can you make it so a+b+c= 418? and yes, none of the integers can be more or equal to 180. and none of them can be the same.

Thanks!

Guest Jun 22, 2019
edited by Guest  Jun 22, 2019
edited by Guest  Jun 22, 2019
#4
0

Yes, 418 can be split into a group of three numbers.

418 can be split into 138 + 139 + 141.

418/3 = 139.333333333 and that keeps gong on forever. So the numbers must be around that point somewhere.

138+139+140= 417. We are one number off from 418. So, logically, if we added 1 to one of the numbers, we would get 418.

Since you said all the numbers must be different, we can't add the one to 138 or 139, since then two numbers would be the same.

But, we could add the one two 140, since there are no other numbers in that equation that equal to "141."

So, now our equation is 138+139+141= 418.

Hope this helps!

Jun 23, 2019
#5
+111389
+2

I believe that there are many such three integer patterns.....for example....

64, 176,178   [sum = 418, all are < 180   and all are unique ]

or

66, 174, 178

A computer program could probably  be designed to generate all the possibilities

Jun 23, 2019
edited by CPhill  Jun 23, 2019
#6
+2

I wrote a short code and listed all 3-digit combinations and they came out to =7,260 !!. Here is the code:

a=1; b=1;d=1;p=0;c=a + b + d; if(c==418, goto6, goto8);p=p+1;printp," - ",c, a, b, d; a++;if(a<180, goto4, 0);a=1;b++;if(b<180, goto4, 0);a=1;b=2;d++;if(d<180, goto4,0)

P.S. I hope that he/she doesn't want them ALL listed!.

Guest Jun 23, 2019
#7
+111389
0

Good job, Guest!!!

I think we'll  take your word for it!!!

LOL!!!!

CPhill  Jun 23, 2019