What is the degree measure of angle LOQ when polygon LMNOPQ is a regular hexagon?
Internal angle of regular hexagon = angle P = 120 degrees
So QOP and PQO are 30 degrees each (because there are 180 degrees in a triangle)
OL bisects angle NOP so LOP = 60
Now subtract angle QOP (found earlier to be 30)
60 - 30 = 30 = LOQ