A stick has a length of 5 units. The stick is then broken at two points, chosen at random. What is the probability that all three resulting pieces are SHORTER THAN 3 UNITS
+579 The shortest stick must be between 0 and 5/3. The probability that it is longer than 3 is, therefore:
(5/3 − 3) / (5/3 − 0)
(-4/3) / (5/3)
-4/5
So the probability that both of the shortest sticks are longer than 3 is (-4/5)² = 16/25.
I actually don't really know how to solve this one so I used this https://brainly.com/question/17139544 as a reference.
Hopefully, it is correct
-Vinculum
