Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
790
2
avatar+251 

Hello.

 

I've been working at a 2D kinematics problem for a couple of days now, trying to work out how to do it:

you can view it here:

http://physics.stackexchange.com/questions/101508/finding-an-equation-to-solve-for-the-velocity-of-a-swimmer-crossing-a-river

 

I've worked out the idea of how to get the answer, however I just can't seem to get there.

 

I was hoping someone could explain how they went from step 1 to step 2. I can see some factoring going on but just can't quite work it out.

 

Thank you for your help.

 Mar 23, 2017
 #1
avatar+9675 
0

Step 1: d2vscos45=d1(vrvssin45)

They multiplied out the bracket on the right hand side:

d2vscos45=d1vrd1vssin45

and then they add d1 . vs sin45 each side:

d2vscos45+d1vssin45=d1vr

Factor out the common factor(vs):

vs(d2cos45+d1sin45)=d1vr <-- Step 2!!

 Mar 23, 2017

1 Online Users