+8 Rhombus ABCD has perimeter 148, and one of its diagonals has length 24. How long is the other diagonal?
By definition: 148/4 =37 - measure of one side.
By Pythagoras's Theorem:
24/2 =12 half of the given diagonal
37^2 - 12^2 =D^2, where D =1/2 of the 2nd diagonal
1,369 - 144 =D^2
1,225 =D^2
D =sqrt(1,225)
D =35 - This is 1/2 of the 2nd diagonal
35 x 2 = 70 - measure of the 2nd diagonal.
