number of impairments: 0 1 2 3 4 5 6
frequency: 100 43 36 17 24 9 11
a. Determine the relative frequencies that correspond to the givin frequencies.
b. what proportion of these patients had at most two impairments?
c. use the result of part (b) to determine what proportion of patients had more than two impairments.
** Explain how you got answer please
+33661 First find the total number involved by adding up all the frequencies: T = 100+43+36+17+24+9+11
a. Divide each frequency by the total T
Nbr of impairments 0 1 2 3 4 5 6
relative frequencies 100/T 43/T 36/T 17/T 24/T 9/T 11/T
b. The proportion who had at most 2 impairments = proportion who had exactly 0 impairments + proportion who had exactly 1 impairment + proportion who had exactly 2 impairments = 100/T + 43/T + 36/T
c. Proportion who had more than 2 impairments = 1 - proportion who had at most 2 impairments
or 1 - (100/T + 43/T + 36/T)
You should now be able to fill in the actual numbers.
.
+33661 First find the total number involved by adding up all the frequencies: T = 100+43+36+17+24+9+11
a. Divide each frequency by the total T
Nbr of impairments 0 1 2 3 4 5 6
relative frequencies 100/T 43/T 36/T 17/T 24/T 9/T 11/T
b. The proportion who had at most 2 impairments = proportion who had exactly 0 impairments + proportion who had exactly 1 impairment + proportion who had exactly 2 impairments = 100/T + 43/T + 36/T
c. Proportion who had more than 2 impairments = 1 - proportion who had at most 2 impairments
or 1 - (100/T + 43/T + 36/T)
You should now be able to fill in the actual numbers.
.
