+1886 Let \(A = \left \{ x ∈N | x^2 < 37 \right \}\) and \(B = \left \{ 3k + 1 |k ∈ \left \{ 1, 2, 3, 4 \right \} \right \}\) be sets.
1. List the elements of \(A\) and \(B\), and the subsets of \(B\).
2. For any sets \(A\), \(B\), and \(C\), prove or disprove the claim: If \(A ∈ B\), \(B ∈ C\), then \(A ∈ C\).
3. Show \(\left \{ 12a + 4b |a, b ∈ Z \right \} = \left \{ 4c |c ∈Z \right \}\)
+308 I assume \(N\) is for natural numbers and \(Z\) is for integers.
1.
A = {1, 2, 3, 4, 5, 6}
B = {4, 7, 10, 13}
Subsets of B are any combination of the elements of B (excluding some).
2.
If A is contained within B, and B is contained with C, A is contained within C.
This is, I suppose, one of those annoying proofs which I take for granted and see no way of prooving it other than it is logical. It is here I should also note that I have never studied set theory, and I'm probably getting everything wrong .
3.
{4(3a+b)|a,b \(\in\)Z} = {4c|c\(\in\)Z}
{3a+b|a,b\(\in\)Z}={c|c\(\in\)Z}
3a+b\(\in\)Z
c\(\in\)Z
(I don't know what to do after that....)
Again, I've never studied this, so apologies in advance for faulty logic everywhere.
