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If N is a perfect square and a divisor of 13!, what is the greatest possible value of N?

 Jan 4, 2019
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13! = 6,227,020,800 = 2^10 * 3^5 * 5^2 * 7 * 11 * 13

N =5^2 x 3^4 x 2^10 =2,073,600

 Jan 4, 2019

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