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Let m = 98! + 99! and n = 6^50. Find the number of trailing zeros in m. Find gcd(m, n). Do NOT simplify.

 Jun 18, 2022
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1 - gcd((98!+99!), 6^50)==9978781 2032686921 0670542716 6130077696


2 - 98! + 99! ==942689 0448883247 7456261857 4305724247 3809693764 0789516634 9423877729 4707070023 2237988829 7615920772 9119823605 8505886084 6042941264 7567360000 0000000000 0000000000 [24 trailing zeros]

 Jun 18, 2022

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