Let n be a positive integer with exactly 3 positive prime divisors. If n^2 has 27 divisors, how many does n have?
n^2 must be factored as a^2 * b^2 * c^2
So n must be factored as ( a^2 * b^2 * c^2)^(1/2) = a * b * c
So n has (1+1) * ( 1 + 1) * (1 + 1) = 8 divisors