+0  
 
0
92
3
avatar

Suppose $(b_a)^2=71_a$, where $a$ and $b$ represent two distinct digits. If $b=a-1$, find $a$.

Guest Jun 16, 2018
 #1
avatar
+1

I think the question is about 2 numbers a, b in other bases. For example: 8^2 in base 9 =71 in base 9.

Since it says: b=a - 1, then since b=8 and a =9, then b=9 - 1=8, which agrees with above.

Guest Jun 16, 2018

37 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.