Walter, Agnes, and Holly are making beaded lizards. Walter has 476 green beads and 32 red beads. Agnes has 104 green beads and 16 red beads. Holly has 34 green beads and 8 red beads. They all share their beads so as to make the largest possible number of lizards. If a beaded lizard requires 34 green beads and 8 red beads, what is the number of green beads left over?

Guest Dec 11, 2020

#1**0 **

Green beads=476 + 104 + 34 =614 Total of green beads.

Red beads =32 + 16 + 8 =56 Total of red beads.

Since they only have 56 red beads and each lizard requires 8 red beads, therefore: 56/8 =7 lizards - is the maximum number they can make.

And since each lizard requires 34 green beads, therefore: 34 x 7 =238 green beads will be needed to make 7 lizards.

614 - 238 =376 green beads will be leftover.

Guest Dec 11, 2020