Find the sum of the positive square free divisors of 6000.
Note: A natural number is square free if it is not the multiple of any perfect square greater than 1.
\(\phantom{5400}\)
(1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 125, 150, 200, 240, 250, 300, 375, 400, 500, 600, 750, 1000, 1200, 1500, 2000, 3000, 6000)==40 divisors
(1, 2, 3, 5, 6, 10, 15, 30)==72 - sum of all square-free divisors of 6,000
Note: You may drop 1 from the list since it is its own square!
