Find the greatest prime divisor of the value of the arithmetic series
1 + 2 + 3 + \dots + 135 + 136 + 137 + 138 + 139 + 140.
So for this problem, let's use the arithmetic series formula.
We find the sum is (140+1)(70)2, which is 141∗35. Now that we have a factorization, we can easily find the greatest prime divisor.
The prime factorization is 3∗5∗7∗47, so the greatest prime divisor is 47.
Thanks! :)