+625 Find the last two digits of $16*{37}$.
(Compute the remainder when $16*{37}$ is divided by 100.)
+1804 Since both numbers we are multiplying are small, we can easily just compute it.
We find that
\(16*37=592\)
Taking the modulo for 100, we find that
\(592 \equiv 92\pmod{100}\)
So 92 is our final answer/
Thanks! :)
