What is the sum of the following sequence: 1^-6 + 3^-6 + 5^-6 + 7^-6 + 9^-6 +.........to infinity.
Any help or hint would be greatly appreciated. Thank you.
+26367 What is the sum of the following sequence:
\(1^{-6} + 3^{-6} + 5^{-6} + 7^{-6} + 9^{-6} + \ldots\) to infinity.
\(\begin{array}{|rcll|} \hline 1^{-6} + 3^{-6} + 5^{-6} + 7^{-6} + 9^{-6} + \ldots &=& 1+\dfrac{1}{3^6}+\dfrac{1}{5^6}+\dfrac{1}{7^6}+\dfrac{1}{9^6}+ \ldots \\ &=& \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} \\ \hline \end{array}\)
zeta-function:
\(\begin{array}{|rcll|} \hline \zeta(s) &=& 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \\ \zeta(s)\left(1-\dfrac{1}{2^s} \right) &=& \left( 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \right) \left(1-\dfrac{1}{2^s} \right) \\ &=& \left( 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \right) \\ && -\left(\dfrac{1}{2^s}+\dfrac{1}{4^s}+\dfrac{1}{6^s}+\dfrac{1}{8^s} \right) \\ \mathbf{\zeta(s)\left(1-\dfrac{1}{2^s} \right) } &=& \mathbf{ 1+\dfrac{1}{3^6}+\dfrac{1}{5^6}+\dfrac{1}{7^6}+\dfrac{1}{9^6}+ \ldots } \\ \hline \end{array} \)
with Bernoulli numbers B:
\(\begin{array}{|lrcll|} \hline & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^s} &=& \left(1-\dfrac{1}{2^s} \right) \zeta(s) \quad &| \quad \zeta(2n) = \Big(-1\Big)^{(n-1)} \cdot \dfrac{ (2 \pi)^{2n} } {2(2n)!} B_{2n} \\ \hline s=6: & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} &=& \left(1-\dfrac{1}{2^6} \right) \zeta(6) \quad &| \quad \zeta(2\cdot 3) = \Big(-1\Big)^{(3-1)} \cdot \dfrac{ (2 \pi)^{2\cdot 3} } {2(2\cdot 3)!} B_{2\cdot 3} \\ & & & \quad &| \quad \zeta(6) = \Big(-1\Big)^{2} \cdot \dfrac{ (2 \pi)^{6} } {2(6)!} B_{6} \\ & & & \quad &| \quad \zeta(6) = \dfrac{ 2^6 \pi^6 } { 2\cdot 720} B_{6} \qquad B_6 = \dfrac{1}{42} \\ & & & \quad &| \quad \zeta(6) = \dfrac{ 2^6 \pi^6 } { 2\cdot 720} \cdot \dfrac{1}{42} \\ & & & \quad &| \quad \boxed{\zeta(6) = \dfrac{ \pi^6 } {945} } \\ & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} &=& \left(1-\dfrac{1}{2^6} \right) \dfrac{ \pi^6 } {945} \\ & \mathbf{ \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} } &=& \mathbf{ \dfrac{ \pi^6 } {960 } } \\ \hline \end{array}\)
Bernoulli numbers:
+128406 1 1 1 1 1
___ + ___ + ___ + ____ + ____ + ........ =
1^6 3^6 5^6 7^6 9^6
∞ pi^6
∑ 1/ [2n +1]^6 = _____
n = 0 960
+26367 What is the sum of the following sequence:
\(1^{-6} + 3^{-6} + 5^{-6} + 7^{-6} + 9^{-6} + \ldots\) to infinity.
\(\begin{array}{|rcll|} \hline 1^{-6} + 3^{-6} + 5^{-6} + 7^{-6} + 9^{-6} + \ldots &=& 1+\dfrac{1}{3^6}+\dfrac{1}{5^6}+\dfrac{1}{7^6}+\dfrac{1}{9^6}+ \ldots \\ &=& \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} \\ \hline \end{array}\)
zeta-function:
\(\begin{array}{|rcll|} \hline \zeta(s) &=& 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \\ \zeta(s)\left(1-\dfrac{1}{2^s} \right) &=& \left( 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \right) \left(1-\dfrac{1}{2^s} \right) \\ &=& \left( 1+\dfrac{1}{2^s}+\dfrac{1}{3^s}+\dfrac{1}{4^s}+\dfrac{1}{5^s}+ \ldots \right) \\ && -\left(\dfrac{1}{2^s}+\dfrac{1}{4^s}+\dfrac{1}{6^s}+\dfrac{1}{8^s} \right) \\ \mathbf{\zeta(s)\left(1-\dfrac{1}{2^s} \right) } &=& \mathbf{ 1+\dfrac{1}{3^6}+\dfrac{1}{5^6}+\dfrac{1}{7^6}+\dfrac{1}{9^6}+ \ldots } \\ \hline \end{array} \)
with Bernoulli numbers B:
\(\begin{array}{|lrcll|} \hline & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^s} &=& \left(1-\dfrac{1}{2^s} \right) \zeta(s) \quad &| \quad \zeta(2n) = \Big(-1\Big)^{(n-1)} \cdot \dfrac{ (2 \pi)^{2n} } {2(2n)!} B_{2n} \\ \hline s=6: & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} &=& \left(1-\dfrac{1}{2^6} \right) \zeta(6) \quad &| \quad \zeta(2\cdot 3) = \Big(-1\Big)^{(3-1)} \cdot \dfrac{ (2 \pi)^{2\cdot 3} } {2(2\cdot 3)!} B_{2\cdot 3} \\ & & & \quad &| \quad \zeta(6) = \Big(-1\Big)^{2} \cdot \dfrac{ (2 \pi)^{6} } {2(6)!} B_{6} \\ & & & \quad &| \quad \zeta(6) = \dfrac{ 2^6 \pi^6 } { 2\cdot 720} B_{6} \qquad B_6 = \dfrac{1}{42} \\ & & & \quad &| \quad \zeta(6) = \dfrac{ 2^6 \pi^6 } { 2\cdot 720} \cdot \dfrac{1}{42} \\ & & & \quad &| \quad \boxed{\zeta(6) = \dfrac{ \pi^6 } {945} } \\ & \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} &=& \left(1-\dfrac{1}{2^6} \right) \dfrac{ \pi^6 } {945} \\ & \mathbf{ \sum \limits_{n=0}^{\infty} \dfrac{1}{(2n+1)^6} } &=& \mathbf{ \dfrac{ \pi^6 } {960 } } \\ \hline \end{array}\)
Bernoulli numbers:
