The prime factorization of 2007 is 3^2*223. How many ordered pairs of positive integers (x,y) satisfy the equation $xy^2=2007$?
For positive integers, x = 223 and y = + 3 / y = - 3 and x = 2007 and y = + 1 / - 1.
I believe I already have seen this question, idk.
