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The prime factorization of 2007 is 3^2*223. How many ordered pairs of positive integers (x,y) satisfy the equation $xy^2=2007$?

 Feb 5, 2022
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For positive integers, x = 223 and y = + 3 / y = - 3 and x = 2007 and y = + 1 / - 1.

 

I believe I already have seen this question, idk.

 Feb 6, 2022

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