In how many ways can the numbers 1, 2, 3, 4, 5, 6 be arranged in a row, so that the product of any two adjacent numbers is at least 5?
In how many ways can the numbers 1, 2, 3, 4, 5, 6 be arranged in a row,
so that the product of any two adjacent numbers is at least 5?
You must have the 1 between the 5 and the 6.
The rest of the numbers can be anywhere.
So, consider two cases:
(1) Permutation of 2 3 4 (5 1 6) ..... 4P4 = 24
(2) Permutation of 2 3 4 (6 1 5) ..... 4P4 = 24
Add them together total ..... 48 ways
.