When a prime is divided by 60, the remainder is a composite number. When a second prime is divided by 60, the remainder is a prime. Find the smallest possible value of the second prime.
When a prime is divided by 60, the remainder is a composite number. When a second prime is divided by 60, the remainder is a prime. Find the smallest possible value of the second prime.
2 is the smallest prime. 2 / 60 = 0 R 2 so the remainder is a prime as well.
However, I think that is not the intent of the problem. Let's go larger than 60.
Note the smallest primes – 2, 3, 5, 7, 11, etc – and then add to 60
62 not prime
63 not prime
65 not prime
67 prime and 67 / 60 = 1 R 7 and the remainder is prime as well.
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