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When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes.  What are a, b, and c?

 May 3, 2021
 #1
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If we prime factorize 5002, we get 

 

$5002 -> 2*2501$

$5002-> 2*41*61$

 

$\boxed{2*41*61}$

 May 3, 2021

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