When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?
If we prime factorize 5002, we get
$5002 -> 2*2501$
$5002-> 2*41*61$
$\boxed{2*41*61}$
